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Matlab's FFT function is an effective tool for computing the discrete Fourier transform of a signal The following code examples will help you to understand the 



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[PDF] FFT Tutorial

ELE436:CommunicationSystems

FFTTutorial

1GettingtoKnowtheFFT

DTF,butinmuchlesstime.

Matlaborinreal-timeontheSR770

2ReviewofTransforms

LaplaceTransform:x(t),X(s)whereX(s)=1R

¡1x(t)e¡stdt

¡1x(t)e¡j!tdt

zTransform:x[n],X(z)whereX(z)=1P n=¡1x[n]z¡n n=¡1x[n]e¡jn transformatz=ej.

3UnderstandingtheDFT

understandingofthepropertiesoftheDTFT. regionbetween0andfs. imageofthedatabetween0and0:5fs.

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frequency/fs

Figure1:PlotshowingthesymmetryofaDFT

4MatlabandtheFFT

n=[0:29]; x=cos(2*pi*n/10);

N1=64;

N2=128;

N3=256;

X1=abs(fft(x,N1));

X2=abs(fft(x,N2));

X3=abs(fft(x,N3));

scalesothatitextendsfrom0to1¡1

F1=[0:N1-1]/N1;

F2=[0:N2-1]/N2;

F3=[0:N3-1]/N3;

Ploteachofthetransformsoneabovetheother.

subplot(3,1,1) subplot(3,1,2) subplot(3,1,3)

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N = 64

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N = 128

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N = 256

Figure2:FFTofacosineforN=64,128,and256

repetitionsofthefundamentalperiod. n=[0:29]; x1=cos(2*pi*n/10);%3periods x2=[x1x1];%6periods x3=[x1x1x1];%9periods

N=2048;

X1=abs(fft(x1,N));

X2=abs(fft(x2,N));

X3=abs(fft(x3,N));

F=[0:N-1]/N;

subplot(3,1,1) subplot(3,1,2) subplot(3,1,3)

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3 periods

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6 periods

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9 periods

Figure3:FFTofacosineof3,6,and9periods

impulses.

5SpectrumAnalysiswiththeFFTandMatlab

beentirlybelowfs

2,theNyquistfrequency.

appropriatetoshowthespectrumfrom¡fs n=[0:149]; x1=cos(2*pi*n/10);

N=2048;

X=abs(fft(x1,N));

X=fftshift(X);

F=[-N/2:N/2-1]/N;

plot(F,X), xlabel('frequency/f s') -0.5-0.4-0.3-0.2-0.100.10.20.30.40.50 frequency / fsquotesdbs_dbs2.pdfusesText_4