[PDF] [PDF] Matrices, transposes, and inverses

1 fév 2012 · Definition The identity matrix, denoted In, is the n x n diagonal matrix with all ones on the diagonal I3 = ⎡⎣ 1 0 0 0 1 0 0 0 1 ⎤ ⎦



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[PDF] Matrices, transposes, and inverses

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Matrices, transposes, and inverses

Math 40, Introduction to Linear Algebra

Wednesday, February 1, 2012

1-23 215
4 3 2 4 dotproduct of 2 1 5 and 4 3 2 4 21

Matrix-vector multiplication: two views

1-23 215
4 3 2 =4 1 2 +3 -2 1 +2 3 5 A

1st perspective: A is linear combination of columns of A

?x?x

2nd perspective: A is computed as dot product of rows of A with vector

?x?x

Notice that # of columns of A = # of rows of .

This is a requirement in order for matrix multiplication to be defined. ?x A ?x 1-23 215
4 3 2 =4 1 2 +3 -2 1 +2 3 5 4 21
"inner" parameters must match m x n n x p

Matrix multiplication

For m x n matrix A and n x p matrix B,

the matrix product AB is an m x p matrix. "outer" parameters become parameters of matrix AB What sizes of matrices can be multiplied together? If A is a square matrix and k is a positive integer, we define A k =A·A···A kfactors

Properties of matrix multiplication

Most of the properties that we expect to hold for matrix multiplication do.... A(B+C)=AB+AC(AB)C=A(BC)k(AB)=(kA)B=A(kB)for scalark .... except commutativity!!

In general,

AB?=BA.

Matrix multiplication not commutative

In general,

AB?=BA.

Problems with hoping AB and BA are equal:

BA may not be well-defined.

Even if AB and BA are both defined, AB and BA may not be the same size. Even if AB and BA are both defined and of the same size, they still may not be equal. (e.g., A is 2 x 3 matrix, B is 3 x 5 matrix)(e.g., A is 2 x 3 matrix, B is 3 x 2 matrix) 11 11 12 12 12 12 11 11 33
33
24
24

Truth or fiction?

For n x n matrices A and B, is

Question 1

A 2 -B 2 =(A-B)(A+B)?

Question 2

For n x n matrices A and B, is

(AB) 2 =A 2 B 2

No!!No!!

(A-B)(A+B)=A 2 +AB-BA-B 2 AB-BA ?=0 (AB) 2 =ABAB?=AABB=A 2 B 2

Matrix transpose

A T 15 33
52
-21 A= 135-2
5321

Example

Transpose operation can be viewed as

flipping entries about the diagonal. i.e.,(A T ij =A ji ?i,j. Definition The transpose of an m x n matrix A is the n x m matrix A T obtained by interchanging rows and columns of A, Definition A square matrix A is symmetric if A T = A.

Properties of transpose

(1) (A T T =A (2) (A+B) T =A T +B T (3)

Forascal arc,(cA)

T =cA T (4) (AB) T =B T A T

To prove this, we show that

[(AB) T ij =[(B T A T ij apply twice -- get back to where you started

ExerciseProve that for any matrix A, A

T

A is symmetric.

Special matrices

Definition A square matrix is upper-triangular if all entries below main diagonal are zero. A= 2 1 4 5 060
00-3 Definition A matrix with all zero entries is called a zero matrix and is denoted 0. A= 0000 0000 0000 analogous definition for a lower-triangular matrix Definition A square matrix whose off-diagonal entries are all zero is called a diagonal matrix. A= 3 8 000 0-200 00-40 0001 Definition The identity matrix, denoted I n , is the n x n diagonal matrix with all ones on the diagonal. I 3 100
010 001

Identity matrix

Definition The identity matrix, denoted I n , is the n x n diagonal matrix with all ones on the diagonal. I 3 100
010 001

Important property

of identity matrix

If A is an m x n matrix, then

I m

A = A and AI

n = A.

If A is a square matrix, then

IA = A = AI.

The notion of inverse

Consider the set of real numbers, and say that we have the equation and we want to solve for x.

Exploration

3x = 2What do we do?We multiply both sides of the equation by to obtain

1 3 1 3 (3x)= 1 3 (2)=?x= 2 3 multiplicative inverse of 3 since 1 3 (3)=1

Now, consider the linear system

Theinve rseofamatrix

ExplorationLet'sthinkabo utinversesfirst inthecontextofr ealnum- bers.Saywehav eequation 3x=2 andwe wanttos olveforx.Todoso,multiplybothsidesby 1 3 too btain 1 3 (3x)= 1 3 (2)=?x= 2 3 ForR, 1 3 ist hemultiplicativ einverseof3since 1 3 (3)=1.

Nowconsider thefollowingsy stemof

equations 3x 1 -5x 2 =6 -2x 1 +3x 2 =-1 whichwew anttosolv eforx 1 andx 2

Noticethatweca nrewritethese

equationsas 3-5 -23 A x 1 x 2 ?x 6 -1 b

Howdowei sola tethevectorx=

x 1 x 2 byitse lfontheLHS?

Multiplybothsidesofma trixequatio nby

-3-5 -2-3 -3-5 -2-3 3-5 -23 x 1 x 2 -3-5 -2-3 6 -1 10 01 I x 1 x 2 -13 -9 x 1 x 2 -13 -9

Thus,thesolution to(?)isx

1 =-13and x 2 =-9.

Lecture7Math40,Spring'1 2,P rof.KindredPag e1

Notice that we can rewrite equations as

Theinve rseofamatrix

ExplorationLet'sthinkabo utinversesfirst inthecontextofr ealnum- bers.Saywehav eequation 3x=2 andwe wanttos olveforx.Todoso,multiplybothsidesby 1 3 too btain 1 3 (3x)= 1 3 (2)=?x= 2 3 ForR, 1 3 ist hemultiplicativ einverseof3since 1quotesdbs_dbs21.pdfusesText_27