LIA 2 If f(x) = x -+-1, then f'(2) = (A) 10 (B) 9) (C) 7 (D) 5 (E) 3 f'= 3x2-2x +1 12-4 +1=9 3 Which of the following definite integrals has the same value as (xet' dx ? -7310/7 + 1/3 tatt The graph intersects the horizontal axis at i = 0, t = k,
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[PDF] SAT 2015 Practice Test Answer Explanations SAT Suite of
x − 1 _ 3 = k, which gives x − 1 _ 3 = 3 Multiplying both sides of x − 1 _ 3 = 3 by 3 gives Choices A, C, and D are incorrect because when the given values of x and y are substituted (1, 3), and graph the inequality y > 1 _ 2 x − 1 by
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If = k and k = 3, what is the value of x ? A) 2 B) 4 On Saturday afternoon, Armand sent m text messages each hour for 5 hours, and Tyrone sent p text messages
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For each positive integer k, let P2k = Xk and q2k = 2Yk Then 8), while if y is odd, then x 2 == 5 (mod 8); neither congruence for x 2 is realizable try various values of x Z2 - 5y2 = 4 and (x, y, z) = (2,1,3), (2, 8,18), (2,21,47), and x = 3 to
[PDF] SAT 2015 Practice Test Answer Explanations SAT Suite of
Choices A, C, and D are incorrect because when the given values of x and y are substituted k = 4 Since the sides of an equation were squared while solving √ _ 2k2 + 17 − 7 = 0, and 3 are, respectively, (−4, 1), (3 _ 2 , 1), and (3, 1)
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Which values of x are solutions of the equation x' +X- - 2x = 0? (1) 3 = 8+2n What is the remainder when x - 8x² +12 is divided by x + 2 ? k=3 1) 4 2) 12
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3) E) Since all of the numerators are even, they all must yield integers when divided by 2 6/2 = 3 Since -5 is 3 less than -2, the point of the reflection must have an x-value 3 more than - Therefore, the point (1, 3) must also be on this parabola Now substitute 3 for k and 3 for t in the original equation and solve for C(t)
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1 a) Find the range of values of k for which the quadratic equation kx2 + 3x – 5 = 0 a=k 6=3 C =-5 20 X cu a = 2 bo- 2=-6 6) 201²-x-670 21x²4x + 3x-670 21( x-2) + 3(x-2) C --3 103 +5X - 63 -3 70 530 (2x+1)-3(2)(+1) 70 (ulti) (5 X-3) 70 If you drew y=(241) (506-3) where does it If drew y= (1-3) (443) crosses x Būs
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X= 104 P O I 5 For which of the following values of k will the equation 5(2x+3) – 8 (1) k=6 ((3) k=7 ) (2) k=-5 (4) k =15 10x +15-8 =10X TK 10x + 7 = 10x tk 2 2 When the expression 5x(2x + 5) – x? 76-1)-3=2(21-1) 3) 13tity 7 -10 = -10
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LIA 2 If f(x) = x -+-1, then f'(2) = (A) 10 (B) 9) (C) 7 (D) 5 (E) 3 f'= 3x2-2x +1 12-4 +1=9 3 Which of the following definite integrals has the same value as (xet' dx ? -7310/7 + 1/3 tatt The graph intersects the horizontal axis at i = 0, t = k,
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for x S 2 for x > 2 3 The function f is defined above For what value of k, if any, is f continuous at x = 2 ? (A) 1 (B) 2 (C) 3 (D) 7 (E) No value of k will make f continuous at x = 2 X-3X+9=kX+ 2 13 279 R 2 + (14) m = f(1) = 3 yay=3(x-1)
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