[PDF] [PDF] The assignment statement - Cornell Computer Science

The assignment statement is used to store a value in a variable We can abbreviate a declaration of c followed by an assignment of 25 to it, using an initializing 



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[PDF] Chapter 7 Expressions and Assignment Statements

Essence of imperative languages is dominant role of assignment statements A + - B * C // is illegal 2 Associativity ▫ The operator associativity rules for 



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Chapter7 Expression and Assignment Statement b = 9; c = 5; a = b = c; 5 is assigned to both a and b because of the right-to-left associativity of the = operator



[PDF] The assignment statement - Cornell Computer Science

The assignment statement is used to store a value in a variable We can abbreviate a declaration of c followed by an assignment of 25 to it, using an initializing 



[PDF] 1 The Assignment Statement and Types - Cornell CS

Assignment Statement: WHERE TO PUT IT = RECIPE FOR A VALUE This: Is the same as: A + B*C A + (B*C) -A**2/4 -(A**2)/4 A*B/C*D ((A*B)/C)*D 



[PDF] Chapter 7 Expressions and Assignment statements

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The assignment statement 1 The assignment statement is used to store a value in a variable. As in most programming languages these days, the assignment statement has the form: = ; For example, once we have an int variable j, we can assign it the value of expression 4 + 6: int j; j= 4+6; As a convention, we always place a blank after the = sign but not before it. You don't have to follow this convention. Our reasons for it are explained on p. 27 of Gries/Gries. Once we have variables with values, we can use those variables in expressions. For example, we can evalu-ate the expression consisting simply of j, or the expression 2*j, and we can store the value of expression j+1 in another variable k: j 2*j int k; k= j + 1; k You must memorize how the assignment statement is executed, or carried out. If asked, you should say: Evaluate the and store its value in the . Please memorize this definition of how to execute the assignment statement. In order to be sure that you under-stand it, we execute a series of assignments, showing how the variables change. Here's variables j and k, with the values computed by what we have done so far. We now execute a se-quence of three assignments. Add 2 to j and store the result in j. subtract k from j and store the result in k, and store 0 is in j. j= j + 2; k= j - k; j= 0; As we carry out the assignments, we change the values of the variables. We do not draw the variables again. There is only one variable j, and its value is changed whenever j is assigned a new value. The initializing declaration We can abbreviate a declaration of c followed by an assignment of 25 to it, using an initializing declaration: int c= 25; Actually, any expression may be used - the expression need not be a constant. It is important to realize that this is simply a combination of a declaration and an assignment. Writing two such initializing declarations for the same variable will not work because only one declaration per variable is allowed. int m= c+1; int m= 45; // illegal because m has already been declared The types of variable and expression must match In a Java assignment, the types of the variable and expression must match. For example, if one is a boole-an, the other must be also, and if one is a String, the other must be a String. This is a consequence of the strong typing principle. For numeric types, there is a bit more leeway. You know that there are types byte, short, int, and long which have increasingly larger sets of values, and there are two floating point, or real-number, types, float and double. These move from the so-called narrowest type byte to the widest type, double.

The assignment statement 2 The rule for an assignment of an expression that is a number is that the type of the variable has to be at least as wide as the type of the expression. For example, if we have, if we have a byte variable b and an int variable i, both of which contain 0, it is legal to assign b to i but illegal to assign i to b. byte b= 0; int i= 0; i= b; b= i; // illegal The reason for the rule should be clear. Assigning a wider-type value to a narrower-type variable may lose in-formation or result in overflow of some sort. For example, how could 6000 be stored in a byte variable? You might think that Java would allow an assignment of an int to a byte but would complain at runtime if the int value were too big. However, this would violate the strong typing principle, as designed in Java.

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