[PDF] [PDF] Conversion from Molarity to Molality - justonly

[PDF] Molality

The molality of a solution is calculated by taking the moles of solute and dividing by the kilograms of solvent Page 4 Molality Examples Example #1 - Suppose we 

[PDF] Conversion from Molarity to Molality - justonly

Problem: Find the molality of 18 M H2SO4 This solution has a density of 1 84 g/ mL Step 1 Make an assumption Assume you have 1 

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/dsoln) dsoln = density of the solution for m = concentration as molality: c = m (1 kg) 1000 g + m (1 kg) MB dsoln (1000 mL/1 L) ≅ m dsoln (1 kg mL g -1 L -1 )  

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Molality (mol/kg) = m moles of solute/ kg of solvent = m 4 Molarity (mol/L) = M moles of solute/ liter of solution = M 5 Normality (equiv/ L) = N equivalents of 

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Conversion from Molarity to Molality

Problem:Find the molality of18 M H2SO4.This solution has a density of1.84 g/mL.

Step 1. Make an assumption.

Assume you have 1 L of solution.This is a very important step and the amount of solution is not given but you need to have a specific quantity to do the calculations and one liter is the best assumption for this problem.

Step 2. Find the total mass of the solution.

Multiply 1 L X the density (1.84 g/mL) X 1000 mL/L. This gives 1840 grams of solution.

Step 3. Calculate the grams of the solute.

18M means 18 moles of sulfuric acid per one liter of solution. Convert 18 moles to

grams. The molar mass of sulfuric acid is 98.09 g/mol.

18 moles X 98.09 g/mol = 1765.62 grams of sulfuric acid.

Step 4. Calculate the grams of the solvent.

1840 grams of solution - 1765.62 grams of solute = 74.38 grams solvent.

Step 5. Calculate the molality.

18 moles solute / 0.07438 kg solvent =242 molal H2SO4

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