[PDF] ADVANCED PROGRAMME MATHEMATICS CORE MODULE: CALCULUS AND



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GRADE 12 EXAMINATION

NOVEMBER 2015

ADVANCED PROGRAMME MATHEMATICS

CORE MODULE: CALCULUS AND ALGEBRA

MARKING GUIDELINES

Time: 2 hours 200 marks These marking guidelines are prepared for use by examiners and sub-examiners, all of whom are required to attend a standardisation meeting to ensure that the guidelines are consistently interpreted and applied in the marking of candidates' scripts. The IEB will not enter into any discussions or correspondence about any marking guidelines. It is acknowledged that there may be different views about some matters of emphasis or detail in the guidelines. It is also recognised that, without the benefit of attendance at a standardisation meeting, there may be different interpretations of the application of the marking guidelines. GRADE 12 EXAMINATION: ADVANCED PROGRAMME MATHEMATICS - Page 2 of 10 CORE MODULE: CALCULUS AND ALGEBRA - MARKING GUIDELINES

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2 12 2 2 11 2 22
1 22 1 22 12 3 n n log log log n log n n

QUESTION 1

1.1 (a) 3 x e ln3x ln3

0,35 x

(4) (b) tan 2x

1,107 xk

tan 2 x

1,107 xk

1,11 2,04 4,25 5,18x or or or (6)

(c) 12 2 log log 2 n xx 22
log log 2xn x 22
11 log log 2 22
n OR 12n

3n (4)

1.2 (a) (1)

70 1 22 P

92 C (2)

(2) Limit as t

22PC (2)

(b)

55 70 1,2 22

t

40 70 1,2 22

t

4,1245mints 7,449mints

4,12 7,45t (7)

[25] GRADE 12 EXAMINATION: ADVANCED PROGRAMME MATHEMATICS - Page 3 of 10 CORE MODULE: CALCULUS AND ALGEBRA - MARKING GUIDELINES

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QUESTION 2

Prove true for n = 1:

LHS = 2

5 1 24

Which is a multiple of

8

Assume true for n = k:

2 5 18 k p pN

Prove true for n = k + 1:

21
22
2 51

5 .5 1

5 81

25 8 1 1

200 24

8 25 3 whichisamultipleof 8.

k k k

But p by assumption

p p p Hence, we have shown that if the expression is divisible by 8 by any one natural value of n then it is also true for the next consecutive value. But it is true for n =1, therefore also true for n =2, 3 , 4 and so on for all natural values of n. OR by the P.M.I. the statement is true for n [14]

QUESTION 3

3 .1 22
a bi a bi ab 22
22
2 a b abi ab 22
22
ab real part ab (7) 3.2

One other solution is

37xi .

2 2 37

6 9 49

6 58 0xi

xx xx

By inspection:

232
(2 1)( 6 58) 258 x x x x px qx p = -13 q = 122 (10) [17] GRADE 12 EXAMINATION: ADVANCED PROGRAMME MATHEMATICS - Page 4 of 10 CORE MODULE: CALCULUS AND ALGEBRA - MARKING GUIDELINES

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QUESTION 4

4.1 tan 3 2

1 3( ) r Pythag

3 radians

2r (6)

4.2

Area of sector =

2 2 2 1 2 1 2. 23
2,09 r units tan2

3,46AB

AB units

Area of

OAB 2 1

2 3,46

2

3,46units

Shaded area = 3,46 - 2,09 = 1,37 units

2 (9) [15] GRADE 12 EXAMINATION: ADVANCED PROGRAMME MATHEMATICS - Page 5 of 10 CORE MODULE: CALCULUS AND ALGEBRA - MARKING GUIDELINES

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QUESTION 5

5.1 (a) 1 () 2 3px x 2 2 '( ) 2 3 (3) 3 23
px x x (4) (b) 1 23
x y 1 32y
x 1 12 3 x px x (4) 5.2 (a) ()pqx (3) (b) ()r px (3) 5.3 2 6 25
x gx x 2 2

2 52 62'( )25 x xxgxx

22

0 4 10 2 12 x xx

2

0 56 xx

6; 1 xx

6; 1 yy (8)

[22] GRADE 12 EXAMINATION: ADVANCED PROGRAMME MATHEMATICS - Page 6 of 10 CORE MODULE: CALCULUS AND ALGEBRA - MARKING GUIDELINES

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QUESTION 6

(a) (i) There will be two x-intercepts unless a factor cancels, i.e. (x + 1) gives p = 5. (2x - 1) gives p = -8,5 (ii) p = 5 and p = -8,5 ( see above) Denominator is a perfect square, i.e. x = -4 or x = 4. (b) (i) 2 2 21 1
21

54 4 1

xx xx fx xx x x

1 0,5 1 4x or x or x

(ii) x-intercepts: x = -1; x = 0.5 y-intercept: y = -0.25 vertical asymptotes: x = 1 and x = 4 horizontal asymptote: y = 2 shape

4 1 0.5

-1 GRADE 12 EXAMINATION: ADVANCED PROGRAMME MATHEMATICS - Page 7 of 10 CORE MODULE: CALCULUS AND ALGEBRA - MARKING GUIDELINES

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6.2 (a) Prove continuity: Prove differentiability: 0 0 lim ( ) 3 lim ( ) 33
(3) 3 3 0 x x gx gx g continuous at x 0 0 0 0 lim '( ) lim ( 2 1) 1 lim '( ) lim 1 1 0 x xquotesdbs_dbs16.pdfusesText_22