[PDF] Math 2331 { Linear Algebra



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2 Solve: 10x4 - 9x2 + 2 = 0

Jun 26, 2011 · c) ther is no solution a) solution set is {x -2 < x < -1, x > 10 } 38 Add Simplify if possible 2y + y y2-16 y-4 2y y2"16 + y y"4 = y(y+6) y2"16 39 For the following equation, state the value of the discriminant and then describe the nature of the solution: 15x2 + 5x – 14 = 0 The value of discriminant is: a> The equation has one real



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SOLVING SOLUTION AND MIXTURE VERBAL PROBLEMS 1 Solution Problems

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Math 2331 { Linear Algebra

Parallel solution sets of Ax = b and Ax = 0 Theorem Suppose the equation Ax = b is consistent for some given b, and let p be a solution Then the solution set of Ax = b is the set of all vectors of the form w = p+ v h, where v is any solution of the homogeneous equation Ax = 0 Jiwen He, University of Houston Math 2331, Linear Algebra 10 / 12



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13 Congruences - NIU

a solution if an only if gcd(a,n) is a divisor of b Also note that the congruence is stated modulo 90, and so the most satisfying answer is given in terms of congruence classes modulo 90 Solution: We have gcd(42,90) = 6, so there is a solution since 6 is a factor of 12 Solving the congruence 42x ≡ 12 (mod 90) is equivalent to solving the



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1 In T(n) = a * T(n/b) + f(n) , a refers to

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Solution This cannot be a probability density function If c= 0, then it does not integrate 1 For any c6= 0, there is an interval in −2 ≤ x≤ 2 over which the integral is negative, and therefore does not represent a probability over this interval 2 Suppose that f(x) = (c(3x−x2) if 0 ≤ x≤ 2 0 otherwise

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1.5 Solutions Sets of Linear Systems

Math 2331 { Linear Algebra

1.5 Solutions Sets of Linear Systems

Jiwen He

Department of Mathematics, University of Houston

jiwenhe@math.uh.edu math.uh.edu/jiwenhe/math2331Jiwen He, University of HoustonMath 2331, Linear Algebra1 / 12

1.5 Solutions Sets of Linear SystemsHomogeneousNonhomogeneous

1.5 Solutions Sets of Linear SystemsHomogeneous System

Nontrivial Solutions

Writing Solution Set in Parametric Vector Form

Nonhomogeneous System

Theorem: Solutions of Nonhomogeneous System

Writing Solution Set in Parametric Vector Form

Jiwen He, University of HoustonMath 2331, Linear Algebra2 / 12

1.5 Solutions Sets of Linear SystemsHomogeneousNonhomogeneous

Homogeneous System

Homogeneous System

Ax=0 (Aismnand0is the zero vector inRm)Example x

1+ 10x2= 0

2x1+ 20x2= 0

Corresponding matrix equationAx=0:

1 10 2 20 x1 x 2 =0 0

Trivial solution: x=0

0 orx=0Jiwen He, University of HoustonMath 2331, Linear Algebra3 / 12

1.5 Solutions Sets of Linear SystemsHomogeneousNonhomogeneous

Homogeneous System: Nontrivial Solutions

The homogeneous systemAx=0alwayshas thetrivial solution, x=0.Nontrivial Solution Nonzero vector solutions are callednontrivial solutions.Example (cont.)

Donontrivialsolutions exist?1 10 0

2 20 0

1 10 0

0 0 0

Consistent system with a free variable has innitely many solutions.A homogeneous equationAx=0has nontrivial solutions if

and only if the system of equations has. Jiwen He, University of HoustonMath 2331, Linear Algebra4 / 12

1.5 Solutions Sets of Linear SystemsHomogeneousNonhomogeneous

Homogeneous System: Example 1

Example (1)

Determine if the following homogeneous system has nontrivial solutions and then describe the solution set.

2x1+ 4x26x3= 0

4x1+ 8x210x3= 0Solution:There is at least one free variable (why?)

=)nontrivial solutions exist

2 46 0

4 810 0

s1 23 0

4 810 0

s1 23 0

0 0 2 0

s

1 2 0 0

0 0 1 0

=)x 1= x

2is free

x

3=Jiwen He, University of HoustonMath 2331, Linear Algebra5 / 12

1.5 Solutions Sets of Linear SystemsHomogeneousNonhomogeneous

Homogeneous System: Example 1 (cont.)

x=2 4x 1 x 2 x 33
5 =2 42x2
x 2 03 5 =2 42
1 03 5 =x2v

Graphical representation:

solution set = spanfvg= line through0inR3Jiwen He, University of HoustonMath 2331, Linear Algebra6 / 12

1.5 Solutions Sets of Linear SystemsHomogeneousNonhomogeneous

Nonhomogeneous System: Example 2

Example (2)

Describe the solution set of

2x1+ 4x26x3= 0

4x1+ 8x210x3= 4

( same left side as in the previous example)Solution:

2 46 0

4 810 4

row reduces to1 2 0 6

0 0 1 2

x=2 4x 1 x 2 x 33
5 =Jiwen He, University of HoustonMath 2331, Linear Algebra7 / 12

1.5 Solutions Sets of Linear SystemsHomogeneousNonhomogeneous

Nonhomogeneous System: Example 2 (cont.)

x=2 46
0 23
5 +x22 42
1 03 5 =p+x2v

Graphical representation:

Parallel solution sets ofAx=0&Ax=bJiwen He, University of HoustonMath 2331, Linear Algebra8 / 12

1.5 Solutions Sets of Linear SystemsHomogeneousNonhomogeneous

Nonhomogeneous System: Recap of Previous Two

ExamplesExample (1. Solution ofAx=0)x=x22

42
1 03 5 =x2v x=x2v= parametric equation of line passing through0andvExample (2. Solution ofAx=b)x=2 46
0 23
5 +x22 42
1 03 5 =p+x2v x=p+x2v= parametric equation of line passing throughp parallel tovJiwen He, University of HoustonMath 2331, Linear Algebra9 / 12

1.5 Solutions Sets of Linear SystemsHomogeneousNonhomogeneous

Nonhomogeneous System: Theorem

Parallel solution sets of

Ax=bandAx=0Theorem

Suppose the equationAx=bis consistent for some givenb, and letpbe a solution. Then the solution set ofAx=bis the set of all vectors of the formw=p+vh, wherevhis any solution of the homogeneous equationAx=0.Jiwen He, University of HoustonMath 2331, Linear Algebra10 / 12

1.5 Solutions Sets of Linear SystemsHomogeneousNonhomogeneous

Nonhomogeneous System: Example

Example

Describe the solution set of 2x14x24x3= 0; compare it to the solution set 2x14x24x3= 6:Solution:Corresponding augmented matrix to 2x14x24x3= 0:

244 0(ll-in)

Vector form of the solution:

v=2

42x2+ 2x3

x 2 x 33
5 =2 42
1 03 5 +2 42
0 13 5

Corresponding augmented matrix to 2x14x24x3= 6:

244 6(ll -in)Jiwen He, University of HoustonMath 2331, Linear Algebra11 / 12

1.5 Solutions Sets of Linear SystemsHomogeneousNonhomogeneous

Nonhomogeneous System: Example (cont.)

Vector form of the solution:

v=2

43 + 2x2+ 2x3

x 2 x 33
5 =2 43
5 +2 42
1 03 5 +2 42
0 13

5Parallel Solution Sets ofAx=0andAx=bJiwen He, University of HoustonMath 2331, Linear Algebra12 / 12

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