Assembly Language Programming of 8085
For e.g. assembly language of 8085 is different than that of Motorola 6800 microprocessor. Page 8. Microprocessor understands Machine Language only! •
8080/8085 ASSEMBLY LANGUAGE PROGRAMMING M.ANUAL
This manual describes programming with Intel's assembly language. ISIS-II 8080/8085 MACRO ASSEMBLER OPERATOR'S MANUAL 9800292.
INSTRUCTION SET OF 8085
memory location specified by the contents of the register pair. Example: STAX B. Page 13. Data Transfer Instructions. Opcode.
Assembly Language Programming of 8085
For e.g. assembly language of 8085 is different than that of Motorola 6800 microprocessor. Page 6. Microprocessor understands Machine Language only! •
ASSEMBLY LANGUAGE TUTORIAL - Simply Easy Learning by
Assembly language is converted into executable machine code by a utility program referred to as an assembler like NASM MASM etc. Audience. This tutorial has
Lecture Note On Microprocessor and Microcontroller Theory and
mnemonics which forms the assembly language. The 8085 microprocessor is an 8-bit processor available as a 40-pin IC package and uses +5. V for power.
Assembly language programming: 8085 program to add two 8 bit
Problem – Write an assembly language program to add two 8 bit numbers stored at address 2050 and address 2051 in 8085 microprocessor. The starting.
MICROPROCESSOR LAB MANUAL EEC-553
8085 Microprocessor programming kit instruction coding sheet. SCIENTECH-8085. 1. 2. Power supply. A.C (230V Mains). DESCRIPTION/ALGORITHM:-.
Appendix A: 8085 Instruction Set by Opcode
Microelectronics and Microprocessor-based Sy stems. Data Transfer Group. These instructions transfer data between registers and memory.
8080/8085 ISSEMBL Y LANGUAGE PROGRiMMING MANUAL
Description of the assembler. Overview of 8080 hardware and instruction set. Description of 8D80/8085 differences. ASSEMBLY LANGUAGE CONCEPTS.
INSTRUCTION SET OF 8085
Instruction Set of 8085
yAn instruction is a binary pattern designed inside a microprocessor to perform a specific function. yThe entire group of instructions that a microprocessor supports is called Instruction Set. y8085 has 246instructions. yEach instruction is represented by an 8-bit binary value. yThese 8-bits of binary value is called Op-Codeor Instruction Byte.Classification of Instruction Set
Data Transfer Instruction
Arithmetic Instructions
Logical Instructions
Branching Instructions
Control Instructions
Data Transfer Instructions
These instructions move data between registers, or between memory and registers. These instructions copy data from source to destination. While copying, the contents of source are not modified.Data Transfer Instructions
OpcodeOperandDescription
MOVRd, Rs
Rd, MM, RsCopy from source to destination.
yThis instruction copies the contents of the source register into the destination register. yThe contents of the source register are not altered.yIf one of the operands is a memory location, its location is specified by the contents of the HL registers.
yExample:MOV B, C yMOV B, M yMOV M, CData Transfer Instructions
OpcodeOperandDescription
MVIRd,Data
M, DataMove immediate 8-bit
yThe 8-bit data is stored in the destination register or memory. yIf the operand is a memory location, its location is specified by the contents of the H-L registers. yExample:MVI A, 57H yMVI M, 57HData Transfer Instructions
OpcodeOperandDescription
LXIReg.pair, 16-bit
dataLoad register pair immediate yThis instruction loads 16-bit data in the register pair. yExample:LXI H, 2034 HData Transfer Instructions
OpcodeOperandDescription
LDA16-bit addressLoadAccumulator
yThe contents of a memory location, specified by a 16- bit address in the operand, are copied to the accumulator. yThe contents of the source are not altered. yExample:LDA 2034HData Transfer Instructions
OpcodeOperandDescription
LDAXB/D Register PairLoad accumulator indirect
yThe contents of the designated register pair point to a memory location. yThis instruction copies the contents of that memory location into the accumulator. yThe contents of either the register pair or the memory location are not altered. yExample:LDAX BData Transfer Instructions
OpcodeOperandDescription
LHLD16-bit addressLoad H-L registers direct
yThis instruction copies the contents of memory location pointed out by 16-bit address into register L. yIt copies the contents of next memory location into register H. yExample:LHLD 2040 HData Transfer Instructions
OpcodeOperandDescription
STA16-bit addressStore accumulator direct
yThe contents of accumulator are copied into the memory location specified by the operand. yExample:STA 2500 HData Transfer Instructions
OpcodeOperandDescription
STAXReg. pairStore accumulator indirect
yThe contents of accumulator are copied into the memory location specified by the contents of the register pair. yExample:STAX BData Transfer Instructions
OpcodeOperandDescription
SHLD16-bit addressStore H-L registers direct
yThe contents of register L are stored into memory location specified by the 16-bit address. yThe contents of register H are stored into the next memory location. yExample:SHLD 2550 HData Transfer Instructions
OpcodeOperandDescription
XCHGNoneExchange H-L with D-E
yThe contents of register H are exchanged with the contents of register D. yThe contents of register L are exchanged with the contents of register E. yExample:XCHGArithmetic Instructions
These instructions perform the operations like:
Addition
Subtract
Increment
Decrement
Addition
Any 8-bit number, or the contents of register, or the contents of memory location can be added to the contents of accumulator.The result (sum) is stored in the accumulator.
No two other 8-bit registers can be added directly. Example:The contents of register B cannot be added directly to the contents of register C.Subtraction
Any 8-bit number, or the contents of register, or the contents of memory location can be subtracted from the contents of accumulator.The result is stored in the accumulator.
Subtraction is performed in 2's complement form.
If the result is negatiǀe, it is stored in 2's complement form. No two other 8-bit registers can be subtracted directly.Increment / Decrement
The 8-bit contents of a register or a memory location can be incremented or decremented by 1. The 16-bit contents of a register pair can be incremented or decremented by 1. Increment or decrement can be performed on any register or a memory location.Arithmetic Instructions
OpcodeOperandDescription
ADDRMAdd register or memory to accumulator
yThe contents of register or memory are added to the contents of accumulator. yThe result is stored in accumulator. yIf the operand is memory location, its address is specified by H-L pair. yAll flags are modified to reflect the result of the addition. yExample:ADD B or ADD MArithmetic Instructions
OpcodeOperandDescription
ADCRMAdd register or memory to accumulator with
carry yThe contents of register or memory and Carry Flag (CY) are added to the contents of accumulator. yThe result is stored in accumulator. yIf the operand is memory location, its address is specified by H-L pair. yAll flags are modified to reflect the result of the addition. yExample:ADC B or ADC MArithmetic Instructions
OpcodeOperandDescription
ADI8-bit dataAdd immediate to accumulator
yThe 8-bit data is added to the contents of accumulator. yThe result is stored in accumulator. yAll flags are modified to reflect the result of the addition. yExample:ADI 45 HArithmetic Instructions
OpcodeOperandDescription
ACI8-bit dataAdd immediate to accumulator with carry yThe 8-bit data and the Carry Flag (CY) are added to the contents of accumulator. yThe result is stored in accumulator. yAll flags are modified to reflect the result of the addition. yExample:ACI 45 HArithmetic Instructions
OpcodeOperandDescription
DADReg. pairAdd register pair to H-L pair
yThe 16-bit contents of the register pair are added to the contents of H-L pair. yThe result is stored in H-L pair. yIf the result is larger than 16 bits, then CY is set. yNo other flags are changed. yExample:DAD BArithmetic Instructions
OpcodeOperandDescription
SUBRMSubtract register or memory from accumulator
yThe contents of the register or memory location are subtracted from the contents of the accumulator.
yThe result is stored in accumulator. yIf the operand is memory location, its address is specified by H-L pair. yAll flags are modified to reflect the result of subtraction. yExample:SUB B or SUB MArithmetic Instructions
OpcodeOperandDescription
SBBRMSubtract register or memory from accumulator
with borrowyThe contents of the register or memory locationand Borrow Flag (i.e. CY)are subtracted from the contents of the accumulator.
yThe result is stored in accumulator. yIf the operand is memory location, its address is specified by H-L pair. yAll flags are modified to reflect the result of subtraction. yExample:SBB B or SBB MArithmetic Instructions
OpcodeOperandDescription
SUI8-bit dataSubtract immediate from accumulator
yThe 8-bit data is subtracted from the contents of the accumulator. yThe result is stored in accumulator. yAll flags are modified to reflect the result of subtraction. yExample:SUI 45 HArithmetic Instructions
OpcodeOperandDescription
SBI8-bit dataSubtract immediate from accumulator with borrow yThe 8-bit data and the Borrow Flag (i.e. CY) is subtracted from the contents of the accumulator. yThe result is stored in accumulator. yAll flags are modified to reflect the result of subtraction. yExample:SBI 45 HArithmetic Instructions
OpcodeOperandDescription
INRRMIncrement register or memory by 1
yThe contents of register or memory location are incremented by 1. yThe result is stored in the same place. yIf the operand is a memory location, its address is specified by the contents of H-L pair. yExample:INR B or INR MArithmetic Instructions
OpcodeOperandDescription
INXRIncrement register pair by 1
yThe contents of register pair are incremented by 1. yThe result is stored in the same place. yExample:INX HArithmetic Instructions
OpcodeOperandDescription
DCRRMDecrement register or memory by 1
yThe contents of register or memory location are decremented by 1. yThe result is stored in the same place. yIf the operand is a memory location, its address is specified by the contents of H-L pair. yExample:DCR B or DCR MArithmetic Instructions
OpcodeOperandDescription
DCXRDecrement register pair by 1
yThe contents of register pair are decremented by 1. yThe result is stored in the same place. yExample:DCX HLogical Instructions
These instructions perform logical operations on data stored in registers, memory and status flags.The logical operations are:
AND OR XORRotate
Compare
Complement
AND, OR, XOR
Any 8-bit data, or the contents of register, or memory location can logically haveAND operation
OR operation
XOR operation
with the contents of accumulator.The result is stored in accumulator.
Rotate
Each bit in the accumulator can be shifted either left or right to the next position.Compare
Any 8-bit data, or the contents of register, or memory location can be compares for:Equality
Greater Than
Less Than
with the contents of accumulator.The result is reflected in status flags.
Complement
The contents of accumulator can be complemented.
Each 0 is replaced by 1 and each 1 is replaced by 0.Logical Instructions
OpcodeOperandDescription
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