[PDF] 4 Calculations Used in Analytical Chemisty





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4 Calculations Used in Analytical Chemisty

Ex. 4-1. How many moles and millimoles of benzoic acid (M=122.1 g/mol) are Ex 4-5. Describe the preparation of 2.00 L of 0.108 M BaCl2 from BaCl2 · 2H2O.



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4 Calculations Used in Analytical Chemisty 14

4 Calculations Used in Analytical Chemisty

4A SOME IMPORTANT UNITS OF MEASUREMENT

4A-1 Sl Units

SI Base Units

Physical Quantity Name of unit

AbbreviationMass kilogram kg

Length meter m

Time second

s

Temperature kelvin

K

Amout of substance mole

mol

Electric current ampere

A

Luminous intensity candela

cd International system of units (SI)

Prefixes for units

Prefix Abbreviation Multiplier Prefix Abbreviation Multiplier yotta- Y 10

24 deci- d 10

-1 zetta- Z 10 21
centi- c 10 -2 exa- E 10 18 milli- m 10 -3 peta- P 10 15 micro- 10-6 tera- T 10 12 nano- n 10 -9 giga- G 10 9 pico- p 10 -12 mega- M 10 6 femto- f 10-15 kilo- k 10 3 atto- a 10 -18 hecto- h 10 2 zepto- z 10 -21 deca- da 10 yocto- y 10 -24 angstrom (Å) : non-SI unit of length = 0.1 nm = 10 -10 m.

4A-2 The Distinction Between Mass and Weight

Mass: invariant measure of the amount of matter in an object

Weight:

the force of gravitational attraction between that matter and earth

W = m g

W : weight of an object, m : mass,

g : acceleration due to gravity 15

4A-3 The Mole

Avogadro's number (6.022 10

23
the molar mass of formaldehyde CH 2 O molO16.0g

OCH molO 1mol

molH1.0g

OCH molH 2mol

molC12.0g

OCH molC 1mol

222OCH

2 = 30.0 g/mol CH 2 O the molar mass of glucose C 6 H 12 O 6 molO16.0g

OCH molO 6mol

molH1.0g

OCH molH 12mol

molC12.0g

OCH molC 6mol

222OHC

6126
= 180.0 g/mol C 6 H 12 O 6 * Millimole(mmol) = 10 -3 mol

1 mfw = 10

-3 fw no. of moles of a species X ( no. mol A): X XX Mmn

Ex. 4-1.

How many moles and millimoles of benzoic acid (M=122.1 g/mol) are contained in of the pure acid? amount g HBz = (1 mol/122.1 g) = 0.0164 mol HBz amount g HBz = (1 mmol/0.1221 g) = 16.4 mmol HBz

Ex. 4-2.

How many grams of Na

(22.99 g/mol) are contained in 25. of Na 2 SO 4 (142.0 g/mol)? amount Na 2 SO 4 = 25.00 g (1 mol/142.0 g) = 0.17606 mol since 1 mol of Na 2 SO 4 contains 2 mol of Na amount Na = 2 0.17606 mol = 0.35211 mol mass Na = 0.35211 mol 22.99 g/mol = 8.10 g

4B SOLUTIONS AND THEIR CONCENTRATIONS

4B-1 Concentration of Solutions

Molar Concentration (C)

V nC XX solutionmLno.solute mmol no. solutionLno.solute mol no.molarity 16 Ex 4-3 Calculate the molar conc. of ethanol in an aqueous solution that contains

2. of C

2 H 5

OH (46.07 g/mol) in 3.50 L of solution.

no. mol = (1 mol/46.07 g) = 0.04992 mol CC2H5OH = 0.04992 mol/3.50 L = 0.01426 mol/L = 0.0143 M Analytical Molarity: total number of moles of a solute in 1 L solution (How a solution has been prepared?)

Ex: 1.0 M H

2 SO 4 soln Ш dissolving 1.0 mol or H 2 SO 4 in water and diluting to exactly 1.0 L.

Equilibrium or Species Molarity

: the molar conc. of a particular species in a soln. at equilibrium

Formal Concentration (Formality, F)

: analytical concentration

Ex: 1.00 F NaOH or H

2 SO 4

Ш equilibrium molar conc. = 0.00 M

Ex 4-4.

Calculate the analytical and equilibrium molar conc. of the solute species in an aqueous solution that contains 285 mg of trichloroacetic acid (Cl 3 CCOOH, 163.4 g/mol) in 10.0 mL (the acid is 73 % ionized in water). no. mol HA = 285 mg (1 g/1000 mg) (1 mol/163.4 g) = 1.744 10 -3 mol

M174.0LHA mol174.0L1mL 1000

mL 10.0HA mol 101.744 3- HA C HA

Initial 100%

ѳᑽࡕ27% H

0%

73% + A

0%

73% [HA] = 0.174 mol/L 0.27

= 0.047 mol/L = [H 3 O ] = [A-] = CHA - [HA] = 0.174 - 0.047 = 0.127 M Ex 4-5. Describe the preparation of 2.00 L of 0.108 M BaCl

2 from BaCl2

· 2H

2 O (244 g/mol).

2.00 L 0.108 mol/L = 0.216 mol BaCl

2

· 2H

2 O

0.216 mol 244 g/mol = BaCl

2

· 2H

2 O

Dissolve of BaCl

quotesdbs_dbs33.pdfusesText_39
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