Formal Concentration (Formality, F): analytical concentration Ex: 1 00 F NaOH or H2SO4 → equilibrium molar conc = 0 00 M Ex 4-4 Calculate the analytical
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There are two ways of expressing molar concentration: Molar analytical concentration is the total number of moles of a solute, regardless of its chemical state,
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4 Calculations Used in Analytical Chemisty
4A SOME IMPORTANT UNITS OF MEASUREMENT
4A-1 Sl Units
SI Base Units
Physical Quantity Name of unit
AbbreviationMass kilogram kg
Length meter m
Time second
sTemperature kelvin
KAmout of substance mole
molElectric current ampere
ALuminous intensity candela
cd International system of units (SI)Prefixes for units
Prefix Abbreviation Multiplier Prefix Abbreviation Multiplier yotta- Y 1024 deci- d 10
-1 zetta- Z 10 21centi- c 10 -2 exa- E 10 18 milli- m 10 -3 peta- P 10 15 micro- 10-6 tera- T 10 12 nano- n 10 -9 giga- G 10 9 pico- p 10 -12 mega- M 10 6 femto- f 10-15 kilo- k 10 3 atto- a 10 -18 hecto- h 10 2 zepto- z 10 -21 deca- da 10 yocto- y 10 -24 angstrom (Å) : non-SI unit of length = 0.1 nm = 10 -10 m.
4A-2 The Distinction Between Mass and Weight
Mass: invariant measure of the amount of matter in an objectWeight:
the force of gravitational attraction between that matter and earthW = m g
W : weight of an object, m : mass,
g : acceleration due to gravity 154A-3 The Mole
Avogadro's number (6.022 10
23the molar mass of formaldehyde CH 2 O molO16.0g
OCH molO 1mol
molH1.0gOCH molH 2mol
molC12.0gOCH molC 1mol
222OCH
2 = 30.0 g/mol CH 2 O the molar mass of glucose C 6 H 12 O 6 molO16.0gOCH molO 6mol
molH1.0gOCH molH 12mol
molC12.0gOCH molC 6mol
222OHC
6126= 180.0 g/mol C 6 H 12 O 6 * Millimole(mmol) = 10 -3 mol
1 mfw = 10
-3 fw no. of moles of a species X ( no. mol A): X XX MmnEx. 4-1.
How many moles and millimoles of benzoic acid (M=122.1 g/mol) are contained in of the pure acid? amount g HBz = (1 mol/122.1 g) = 0.0164 mol HBz amount g HBz = (1 mmol/0.1221 g) = 16.4 mmol HBzEx. 4-2.
How many grams of Na
(22.99 g/mol) are contained in 25. of Na 2 SO 4 (142.0 g/mol)? amount Na 2 SO 4 = 25.00 g (1 mol/142.0 g) = 0.17606 mol since 1 mol of Na 2 SO 4 contains 2 mol of Na amount Na = 2 0.17606 mol = 0.35211 mol mass Na = 0.35211 mol 22.99 g/mol = 8.10 g4B SOLUTIONS AND THEIR CONCENTRATIONS
4B-1 Concentration of Solutions
Molar Concentration (C)
V nC XX solutionmLno.solute mmol no. solutionLno.solute mol no.molarity 16 Ex 4-3 Calculate the molar conc. of ethanol in an aqueous solution that contains2. of C
2 H 5OH (46.07 g/mol) in 3.50 L of solution.
no. mol = (1 mol/46.07 g) = 0.04992 mol CC2H5OH = 0.04992 mol/3.50 L = 0.01426 mol/L = 0.0143 M Analytical Molarity: total number of moles of a solute in 1 L solution (How a solution has been prepared?)Ex: 1.0 M H
2 SO 4 soln Ш dissolving 1.0 mol or H 2 SO 4 in water and diluting to exactly 1.0 L.Equilibrium or Species Molarity
: the molar conc. of a particular species in a soln. at equilibriumFormal Concentration (Formality, F)
: analytical concentrationEx: 1.00 F NaOH or H
2 SO 4Ш equilibrium molar conc. = 0.00 M
Ex 4-4.
Calculate the analytical and equilibrium molar conc. of the solute species in an aqueous solution that contains 285 mg of trichloroacetic acid (Cl 3 CCOOH, 163.4 g/mol) in 10.0 mL (the acid is 73 % ionized in water). no. mol HA = 285 mg (1 g/1000 mg) (1 mol/163.4 g) = 1.744 10 -3 molM174.0LHA mol174.0L1mL 1000
mL 10.0HA mol 101.744 3- HA C HAInitial 100%
ѳᑽࡕ27% H
0%73% + A
0%73% [HA] = 0.174 mol/L 0.27
= 0.047 mol/L = [H 3 O ] = [A-] = CHA - [HA] = 0.174 - 0.047 = 0.127 M Ex 4-5. Describe the preparation of 2.00 L of 0.108 M BaCl2 from BaCl2
· 2H
2 O (244 g/mol).2.00 L 0.108 mol/L = 0.216 mol BaCl
2· 2H
2 O0.216 mol 244 g/mol = BaCl
2· 2H
2 ODissolve of BaCl
2· 2H
2O in water and dilute to 2.00 L.
17 Ex 4-6. Describe the preparation of 500 mL of 0. Cl from solid BaCl 2· 2H
2 O (244 g/mol).O2HBaCl g 52.4OH2BaCl molOH2BaCl g 244.3 Cl mol 2O2HBaCl mol 1L 500.0LCl mol 0.0740OH2BaCl mass