[PDF] Using the normalcdf function on the TI 89



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Using the normalcdf function on the TI-84

the normalcdf function, not the normal pdf Do not ever use normal pdf Now enter the 4 important numbers in order First, enter the lower boundary



Using the normalcdf function on the TI 89

Consider the weights of 18 month old boys in the U S According to published growth charts, the average weight is approximately 11 8 kg with standard deviation of 1 28 kg



normalcdf - percentage of area under the curve

Day 3 ­ NormalCDF and InvNorm 1 Warm­Up 1 Bob is a 17 year old male who is 68 in tall 17 year old male heights are normally distributed with mean 70 in and standard deviation 2 1 in Sue is a 16 year old female who is 63 in tall 16



The Normal Distribution

NormalCDF: The normalcdf function will give the probability will fall between two user defined limits on either the standard normal curve, or on any arbitrary normal curve The arguments for this function are: Normalcdf[left limit, right limit, mean (????), standard deviation (????)] InvNorm:



What is the difference between NormalPDF and NormalCDF?

We use normalCDF(30, 1000000, 20, 7) It doesn't matter here what number we use as long as it is large enough to be Sure ALL of the results will be included Here, the same percentage of pandas would live to 1000000 as would 1000 or even 100; thus we would get the same result from the normalCDF



Solving Problems Involving Normal Curves Review Sheet

normalcdf(-E99,400,512,68) = 0 0498 d) What is the probability of a student running more than 610 seconds? normalcdf(610,E99,512,68) = 0 0748 e) What is the probability of a student running between 475 and 525 seconds? normalcdf(475,525,512,68) = 0 2826 Given the area (percentile) and find a number corresponding



Chapter 2 Calculator Worksheet Name: - Mr-Barrynet

Normalcdf( left z-score, right z-score) Invnorm( area to the left of the point in question) Outputs a z-score These can also work with any normal distribution: Normalcdf( left value, right value, mean, standard deviation) Invnorm( area to the left of a point, mean, standard deviation) Outputs the actual value of that point



Table 1: Table of the Standard Normal Cumulative Distribution

Table 1: Table of the Standard Normal Cumulative Distribution Function '(z)z 0 00 0 01 0 02 0 03 0 04 0 05 0 06 0 07 0 08 0 09-3 4 0 0003 0 0003 0 0003 0 0003 0 0003

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Usingthenormalcdf functionon

the

TIͲ89

Theseinstructionswill

workfortheTIͲ89 calculator.

Readtheproblemcarefully:

Consider

theweightsof18 month oldboysintheU.S.

According

topublished growth charts,theaverage weightisapproximately11.8 kgwithstandarddeviation of

1.28kg.Calculatethe

percentageof18monthold boysintheU.S.whoweigh between10.5kgand14.4 kg. importantnumbers.

Consider

theweightsof18montholdboysintheU.S.

According

whoweighbetween10.5kgand14.4kg.

First,

identify theaverage. importantnumbers.

Consider

theweightsof18montholdboysintheU.S.

According

whoweighbetween10.5kgand14.4kg.

Next,identify

thestandard deviation. importantnumbers.

Consider

theweightsof18montholdboysintheU.S.

According

whoweighbetween10.5kgand14.4kg.

Now,identifythe

lowerandupper boundaryofthe areayouwant.

Nowyoujustneedtoentertheimportant

numbersintothecalculatorinorder.The rule is:

First:Lowerboundary=10.5

Second:Upperboundary=14.4

Third:Average=11.8

Fourth:StandardDeviation=1.28

We'll gothroughthiskeystrokeby keystroke.

AccesstheStats/Listeditor

on thecalculatorbypressing

APPS.Scrolldownandover

tohighlighttheeditorand pressenter.

IfyouhaveanolderTIͲ89,

PresstheAPPSandtheStats

editorshouldbelisted underFlashApps.Ifitisnot, contactmeandIwillhelp youupdateyourcalculator.

ThenpressF5to

accesstheDISTR menu.

IMPORTANT!!

Youmustchoose

theNormalCdf function,notthe NormalPdf.Donoteverusenormalpdf!!HighlightNormalCdf and hitenter.

Nowenterthe4important

numbersinorder. acertainvalue,yourlowerboundary willbenegativeinfinity.Pressingthe keyandthentheCATALOG buttonwillenterinfinity.Puta negativeinfrontofitwhen necessary,oryoucanuseany numbermorethan5standard deviations above/belowaverage.

Enterthelower

boundary,10.5,and then pressthedown cursor.

Next,entertheupper

boundary,14.4,andthen pressthedowncursor again. If youwantallthenumbers morethanacertainvalue, yourupperboundarywill be positiveinfinity.Use eitheralargepositive numberlike1000inthese cases orenterinfinity.

Entertheaverage,11.8,

and thenpressdown cursorkey. Enter thestandard deviation,1.28,and then pressENTER.Whenyouareinterestedin the averageandstandard deviation.

PressEnteroncemore

togetyouranswer.

Youranswerwillbea

decimal,theproportion orfractionofthearea underthenormal curve.Youmaywantto convertthisnumberto apercentage.

Ouransweris82.39%

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