[PDF] List of Integrals Containing exp(x) - Math info





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1 Intégrales généralisées

Exercice 1. Montrer que l'intégrale de f : t ?? exp(?t) est convergente sur [0 +?[ et. ? +?. 0 exp(?t)dt = 1. Correction : Pour tout x > 0



Intégrales convergentes

9 mai 2012 ?t>A t?e?t ? e?t/2 . Or l'intégrale ? +?. 1 e?t/2 dt converge. En effet :.



Intégrale de Gauss

Intégrale de Gauss La fonction (t x) ??. ? 1. 0 e?(t2+1)x2 ... e?(tx)2 dt ce qui



Formules de Taylor. Applications. 1 Formule de Taylor avec reste

La formule de Taylor avec reste intégral `a l'ordre n s'écrit alors : exp(x)=1+ n. ? k=1 xk k! + xn+1 n! ? 1. 0(1 ? t)n exp(tx) dt.



Correction de linterrogation

?t/2 ? e?t/2. Or l'intégrale ?. ?. A e?t/2dt converge d'après le théorème d'intégrabilité des fonctions exponentielles. Comme ?t ? 0



Résumé sur les Intégrales Impropres & exercices supplémentaires

f(t)dt est divergente. Exemples. (a). On a. / x. 0 e?tdt = 1 ? e?x. Comme lim x?+? e?x = 0 l'intégrale. / +?. 0 e?tdt est convergente et vaut.



EQUATIONS DIFFERENTIELLES I Définition et notation

La solution générale de cette équation sur I est : y0 = k×e-A(t) où A(t) est une primitive de a(t) sur I et 



Python MP PC

TSI Oral



Développement asymptotique de lintégrale de sin(t)/t

t dt. Yves Coudene 16/10/03. L'intégrale ? N. 0 sin t t L'intégrale ? N. 0 e?tx sint dt se calcule explicitement `a l'aide des complexes :.



Etude de la fonction Gamma ?

e?ttx?1 et pour tout x ? R fx : R?+. ? R t. ?? f(x



Asymptotic Expansion of Integrals - University of Utah

Apr 16 2017 · exp t x? t dt: One can show that asymptotically the solution satis es ypxq c ? 3 3? 4xexp 3 x 2 2{3 as xÝÑ8: 1 Asymptotic Notation We begin by de ning asymptotic notations and asymptotic expansion These are useful in describing the limiting behaviour of a function when the argument gets closer to a particular complex number typically 0 or



List of Integrals Containing exp(x) - Math info

Integrals with Trigonometric Functions Z sinaxdx= 1 a cosax (63) Z sin2 axdx= x 2 sin2ax 4a (64) Z sinn axdx= 1 a cosax 2F 1 1 2; 1 n 2; 3 2;cos2 ax (65) Z sin3 axdx= 3cosax 4a + cos3ax 12a (66) Z cosaxdx=



Table of Basic Integrals Basic Forms

e t2dt (60) Z xex dx= (x 1)ex (61) Z xe axdx= x a 1 a2 e (62) Z x2ex dx= x2 2x+ 2 ex (63) Z x2eax dx= x2 a ax 2x a2 + 2 a3 e (64) Z x3ex dx= x3 3x2 + 6x 6 ex (65) Z



List of integrals of exponential functions - Informa?ní systém

List of integrals of exponential functions 3 ( is the modified Bessel function of the first kind) References • Wolfram Mathematica Online Integrator (http:/

What are the different types of integrals?

Integrals Containing sin Integrals Containing tan Integrals Continaing sec Integrals Continaing csc Integrals Containing cot Inverse Trigonometric Functions Hyperbolic Functions

How do you evaluate a definite integral?

Evaluate the definite integral using substitution: ?2 1 1 x3e4x ? 2dx. Integrating functions of the form f(x) = 1 x or f(x) = x ? 1 result in the absolute value of the natural log function, as shown in the following rule. The following formula can be used to evaluate integrals in which the power is ? 1 and the power rule does not work.

What are double integrals?

Double Integrals: Surface Area Triple Integrals Gradient of a Scalar Function Line Integral of a Vector Field Line Integral of a Scalar Field Green's Theorem Divergence of a Vector Field

How do you integrate an exponential function?

Exponential functions can be integrated using the following formulas. Find the antiderivative of the exponential function e ? x. Use substitution, setting u = ? x, and then du = ? 1dx. Multiply the du equation by ? 1, so you now have ? du = dx. Then, Find the antiderivative of the function using substitution: x2e ? 2x3.

Table of Integrals

Basic Forms

Z x ndx=1n+ 1xn+1(1) Z 1x dx= lnjxj(2) Z udv=uvZ vdu(3) Z

1ax+bdx=1a

lnjax+bj(4)

Integrals of Rational Functions

Z

1(x+a)2dx=1x+a(5)

Z (x+a)ndx=(x+a)n+1n+ 1;n6=1 (6) Z x(x+a)ndx=(x+a)n+1((n+ 1)xa)(n+ 1)(n+ 2)(7) Z

11 +x2dx= tan1x(8)

Z 1a

2+x2dx=1a

tan1xa (9) Z xa

2+x2dx=12

lnja2+x2j(10) Z x2a

2+x2dx=xatan1xa

(11) Z x3a

2+x2dx=12

x212 a2lnja2+x2j(12) Z 1ax

2+bx+cdx=2p4acb2tan12ax+bp4acb2(13)

Z

1(x+a)(x+b)dx=1balna+xb+x; a6=b(14)

Z x(x+a)2dx=aa+x+ lnja+xj(15) Z xax

2+bx+cdx=12alnjax2+bx+cj

ba p4acb2tan12ax+bp4acb2(16)

Integrals with Roots

Z pxadx=23 (xa)3=2(17) Z

1pxadx= 2pxa(18)

Z

1paxdx=2pax(19)

Z xpxadx=23 a(xa)3=2+25 (xa)5=2(20) Z pax+bdx=2b3a+2x3 pax+b(21) Z (ax+b)3=2dx=25a(ax+b)5=2(22) Z xpxadx=23 (x2a)pxa(23) Z rx axdx=px(ax)atan1px(ax)xa(24) Z rx a+xdx=px(a+x)alnpx+px+a(25)Z xpax+bdx=215a2(2b2+abx+ 3a2x2)pax+b(26) Z px(ax+b)dx=14a3=2h (2ax+b)pax(ax+b) b2lnapx+pa(ax+b)i (27) Z px

3(ax+b)dx=b12ab28a2x+x3

px

3(ax+b)

b38a5=2lnapx+pa(ax+b)(28) Z px

2a2dx=12

xpx 2a212 a2lnx+px 2a2 (29) Z pa

2x2dx=12

xpa

2x2+12

a2tan1xpa 2x2 (30) Z xpx

2a2dx=13

x2a23=2(31) Z 1px

2a2dx= lnx+px

2a2(32)

Z 1pa

2x2dx= sin1xa

(33) Z xpx

2a2dx=px

2a2(34)

Z xpa

2x2dx=pa

2x2(35)

Z x2px

2a2dx=12

xpx 2a212 a2lnx+px 2a2 (36) Z pax

2+bx+cdx=b+ 2ax4apax

2+bx+c

4acb28a3=2ln2ax+b+ 2pa(ax2+bx+c)(37)

Z xpax

2+bx+c=148a5=2

2pa pax

2+bx+c

3b2+ 2abx+ 8a(c+ax2)

+3(b34abc)lnb+ 2ax+ 2pa pax

2+bx+c

(38) Z 1pax

2+bx+cdx=1pa

ln2ax+b+ 2pa(ax2+bx+c) (39) Z xpax

2+bx+cdx=1a

pax

2+bx+c

b2a3=2ln2ax+b+ 2pa(ax2+bx+c)(40) Z dx(a2+x2)3=2=xa 2pa

2+x2(41)Integrals with Logarithms

Z lnaxdx=xlnaxx(42) Z lnaxx dx=12 (lnax)2(43) Z ln(ax+b)dx= x+ba ln(ax+b)x;a6= 0 (44) Z ln(x2+a2) dx =xln(x2+a2) + 2atan1xa

2x(45)

Z ln(x2a2) dx =xln(x2a2) +alnx+axa2x(46) Z lnax2+bx+cdx=1a p4acb2tan12ax+bp4acb2

2x+b2a+x

lnax2+bx+c(47) Z xln(ax+b)dx=bx2a14 x2 12 x 2b2a 2 ln(ax+b) (48) Z xlna2b2x2dx=12 x2+ 12 x 2a2b 2 lna2b2x2(49)

Integrals with Exponentials

Z e axdx=1a eax(50) Z pxe axdx=1a pxe ax+ip

2a3=2erfipax

where erf(x) =2p Z x 0 et2dt(51) Z xe xdx= (x1)ex(52) Z xe axdx=xa 1a 2 e ax(53) Z x

2exdx=x22x+ 2ex(54)

Z x

2eaxdx=x2a

2xa 2+2a 3 e ax(55) Z x

3exdx=x33x2+ 6x6ex(56)

Z x neaxdx=xneaxa na Z x n1eaxdx(57) Z x neaxdx=(1)na n+1[1 +n;ax]; where (a;x) =Z 1 x ta1etdt(58) Z e ax2dx=ip 2 pa erfixpa (59) Z e ax2dx=p 2 pa erfxpa (60) Z xe ax2dx =12aeax2(61) Z x

2eax2dx =14

r a

3erf(xpa)x2aeax2(62)?

?2014. Fromhttp://integral-table.com, last revised June 14, 2014. This material is provided as is without warranty or representation about the accuracy, correctness or

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1

Integrals with Trigonometric Functions

Z sinaxdx=1a cosax(63) Z sin

2axdx=x2

sin2ax4a(64) Z sin naxdx= 1a cosax2F112 ;1n2 ;32 ;cos2ax (65) Z sin

3axdx=3cosax4a+cos3ax12a(66)

Z cosaxdx=1a sinax(67) Z cos

2axdx=x2

+sin2ax4a(68) Z cos paxdx=1a(1 +p)cos1+pax 2

F11 +p2

;12 ;3 +p2 ;cos2ax (69) Z cos

3axdx=3sinax4a+sin3ax12a(70)

Z (71) Z sin

2axcosbxdx=sin[(2ab)x]4(2ab)

sinbx2bsin[(2a+b)x]4(2a+b)(72) Z sin

2xcosxdx=13

sin3x(73) Z cos

2axsinbxdx=cos[(2ab)x]4(2ab)cosbx2b

cos[(2a+b)x]4(2a+b)(74) Z cos

2axsinaxdx=13acos3ax(75)

Z sin

2axcos2bxdx=x4

sin2ax8asin[2(ab)x]16(ab) sin2bx8bsin[2(a+b)x]16(a+b)(76) Z sin

2axcos2axdx=x8

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