[PDF] Finite Element Methods for 1D Boundary Value Problems





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Finite Element Methods for 1D Boundary Value Problems

Chapter 6

Finite Element Methods

for 1D Boundary Value

Problems

The finite element (FE) method was developed to solve complicated problems in engineering, notably in elasticity and structural mechanics modeling involving el- liptic PDEs and complicated geometries. But nowadays the range of applications is quite extensive. We will use the following 1D and 2D model problems to introduce the finite element method

1D:-u??(x) =f(x),0< x <

1, u(0) = 0, u(1) = 0;

2D:-(uxx+uyy) =f(x,y),(x,y)?Ω, u(x,y)???∂Ω= 0,

whereΩis a bounded domain in(x,y)plane with the boundary∂Ω.

6.1 The Galerkin FE method for the 1D model

We illustrate the finite element method for the 1D two-point BVP -u??(x) =f(x),0< x <1, u(0) = 0, u(1) = 0, using the Galerkin finite element method described in the following steps.

1. Construct a variational or weak formulation, by multiplying both sides of the

differential equation by a test functionv(x)satisfying the boundary conditions (BC)v(0) = 0,v(1) = 0to get -u??v=fv , and then integrating from0to 1 (using integration by parts) to have the 133

134 Chapter 6. Finite Element Methods for 1D Boundary Value Problems

following, 1 0 (-u??v)dx=-u?v???10+? 1 0 u?v?dx 1 0 u?v?dx 1 0 u?v?dx=? 1 0 fv dx,the weak form.

2. Generate a mesh

,e.g., a uniform Cartesian meshxi=ih,i= 0,1,···,n, whereh= 1/n, defining the intervals(xi-1,xi),i= 1,2,···,n.

3. Construct a set of basis functions

based on the mesh, such as the piecewise linear functions(i= 1,2,···,n-1) i(x) =?x-xi-1 hifxi-1≤x < xi, x i+1-x hifxi≤x < xi+1,

0otherwise,

xixi-1xi+1 often called the hat functions, see the right diagram for a hat function.

4. Represent the approximate (FE) solution by a linear combination of the basis

functions uh(x) =n-1? j=1c jφj(x), where the coefficientscjare the unknowns to be determined. On assuming the hat basis functions, obviouslyuh(x)is also a piecewise linear function, although this is not usually the case for the true solutionu(x). Other basis functions are considered later. We then derive a linear system of equations for the coefficients by substituting the approximate solutionuh(x)for the exact solutionu(x)in the weak form?1

0u?v?dx=?1

0fvdx,i.e.,

1 0 u?hv?dx=? 1 0 fvdx,(noting that errors are introduced!) 1 0n-1? j=1c jφ?jv?dx=n-1? j=1c j? 1 0

φ?jv?dx

1 0 fv dx.

6.1. The Galerkin FE method for the 1D model 135

Next, choose the test functionv(x)asφ1,φ2,···,φn-1successively, to get the system of linear equations (noting that further errors are introduced):??1 0

φ?1φ?1dx?

c

1+···+?

?1 0

φ?1φ?n-1dx?

c n-1=? 1 0 fφ 1dx ?1 0

φ?2φ?1dx?

c

1+···+?

?1 0

φ?2φ?n-1dx?

c n-1=? 1 0 fφ 2dx ?1 0

φ?iφ?1dx?

c

1+···+?

?1 0

φ?iφ?n-1dx?

c n-1=? 1 0 fφ idx ?1 0

φ?n-1φ?1dx?

c

1+···+?

?1 0

φ?n-1φ?n-1dx?

c n-1=? 1 0 fφ n-1dx, or in the matrix-vector form: ?c 1 c 2 c n-1??? =???(f,φ1) (f,φ2) (f,φn-1)??? where a(φi,φj) =? 1 0

φ?iφ?jdx,(f,φi) =?

1 0 fφ idx. The terma(u,v)is called a bilinear form since it is linear with each variable (function), and(f,v)is called a linear form. Ifφiare the hat functions, then in particular we get ?2 h-1h 1 h2h-1h 1 h2h-1h 1 h2h-1h 1 h2h???? ?c 1 c 2 c 3 c n-2 c n-1???? 1

0fφ1dx

1

0fφ2dx

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