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Open Problems in Analysis of Boolean Functions

29 Apr 2012 DM] 29 Apr 2012. Open Problems in ... Compiled for the Simons Symposium February 5–11



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arXiv:1204.6447v1 [cs.DM] 29 Apr 2012

Open Problems in

Analysis of Boolean Functions

Compiled for the Simons Symposium, February 5-11, 2012

For notation and definitions, see e.g.

http://analysisofbooleanfunctions.org 2

Correlation Bounds for Polynomials

Statement:Find an explicit (i.e., inNP) functionf: ?n

2→

?2such that we ?2-polynomial p: ?n

2→

?2of degree at most log2n.

Source:Folklore dating back to [

Raz87,Smo87]

Remarks:

• The problem appears to be open even with correlation bound 1/? nre- placing 1/n. • Define the mod

3function to be 1 if and only if the number of 1"s in

its input is congruent to 1 modulo 3. Smolensky [

Smo87] showed that

mod

3has correlation at most 2/3 with every

?2-polynomial of degree at mostc? n(wherec>0 is an absolute constant). For related bounds us- ing his techniques, there seems to be a barrier to obtaining correlation o(1/? n). • Babai, Nisan, and Szegedy [

BNS92] implicitly showed a function inP

which has correlation at most exp(-nΘ(1)) with any ?2-polynomial of degree at most.99log2n; see also [

VW08]. Bourgain [Bou05] (see

also [ GRS05]) showed a similar (slightly worse) result for the mod3 function.

Tomaszewski"s Conjecture

Statement:Leta?

Source:Question attributed to Tomaszewski in [

Guy89]

Remarks:

• The bound of 1/2 would be sharp in light ofa=(1/?

2,1/?2).

• Holman and Kleitman [

HK92] proved the lower bound 3/8. In fact they

provedPrx≂{-1,1}n[|?a,x?| <1]≥3/8 (assumingai?= ±1 for alli), which is sharp in light ofa=(1/2,1/2,1/2,1/2). Talagrand"s “Convolution with a Biased Coin" Conjecture

Statement:Letf:{-1,1}n→

?≥0haveE[f]=1. Fix any 0<ρ<1. Then

Pr[Tρf≥t]

Source:[

Tal89]

Remarks:

• Talagrand in fact suggests the boundO(1 t?logt). • Talagrand offers a $1000 prize for proving this. • Even the “special case" whenf"s domain is ?nwith Gaussian measure is open. In this Gaussian setting, Ball, Barthe, Bednorz, Oleszkiewicz, 3 and Wolff [ BBB+10] have shown the upper boundO(1t?logt) forn=1 and the boundO(loglogt t?logt) for any fixed constant dimension.

Sensitivity versus Block Sensitivity

where sens[f] is the (maximum) sensitivity, maxx|{i?[n]:f(x)?=f(x?i)}|.

Source:[

CFGS88,Sze89,GL92,NS94]

Remarks:

where bs[f] is the “block sensitivity". However the version with degree is equally old, and in any case the problems are equivalent since it is known that bs[f] and deg(f) are polynomially related. • The best known gap is quadratic ([

CFGS88,GL92]) and it is suggested

GL92]) that this may be the worst possible.

Gotsman-Linial Conjecture

Statement:Among degree-kpolynomial threshold functionsf:{-1,1}n→ {-1,1}, the one with maximal total influence is the symmetric onef(x)= sgn(p(x1+···+xn)), wherepis a degree-kunivariate polynomial which al- ternates sign on thek+1 values ofx1+···+xnclosest to 0.

Source:[

GL94]

Remarks:

• The casek=1 is easy. • Slightly weaker version: degree-kPTFs have total influenceO(k)·? n. • Even weaker version: degree-kPTFs have total influenceOk(1)·? n. • The weaker versions are open even in the casek=2. Thek=2 case may be related to the following old conjecture of Holzman: Ifg:{-1,1}n→ ?has degree 2 (forneven), thenghas at most?n n/2?local strict minima. • It is known that bounding total influence byc(k)·? nis equivalent to a boundingδ-noise sensitivity byO(c(k))·? • The “Gaussian special case" was solved by Kane [

Kan09].

• The best upper boundsknown are 2n1-1/2kand 2O(k)·n1-1/O(k)[

DHK+10].

Polynomial Freiman-Ruzsa Conjecture (in the

?n

2setting)

Statement:Suppose??=A?

?n ered by the union of poly(C) affine subspaces, each of cardinality at most|A|.

Source:Attributed to Marton in [

Ruz93]; for the?n

2version, see e.g. [Gre05b]

Remarks:

4 • The following conjecture is known to be equivalent: Supposef: ?n

2→

?n

2satisfiesPrx,y[f(x)+f(y)=f(x+y)]≥?, wherexandyare in-

dependent and uniform on ?n

2. Then there exists a linear function

f: ?n

2→

?n

2such thatPr[f(x)=?(x)]≥poly(?).

• The PFR Conjecture is known to follow from thePolynomial Bo- golyubov Conjecture[

GT09]: LetA??n

2have density at leastα.

ThenA+A+Acontains an affine subspace of codimensionO(log(1/α)). One can slightly weaken the Polynomial Bogolyubov Conjecture by re- placingA+A+AwithkAfor an integerk>3. It is known that any such weakening (for fixed finitek) is enough to imply the PFR Conjec- ture. • Sanders [ San10b] has the best result in the direction of these conjec- tures, showing that ifA? ?n

2has density at leastαthenA+Acontains

99% of the points in a subspace of codimensionO(log4(1/α)), and hence

4Acontains all of this subspace. This suffices to give the Freiman-

Ruzsa Conjecture with 2

O(log4C)in place of poly(C).

• Green and Tao [

GT09] have proved the Polynomial Freiman-Ruzsa

Conjecture in the case thatAis monotone.

Mansour"s Conjecture

Statement:Letf:{-1,1}n→{-1,1}be computable by a DNF of sizes>1 and let??(0,1/2]. Thenf"s Fourier spectrum is?-concentrated on a collectionF

Source:[

Man94]

Remarks:

• Weaker version: replacingsO(log(1/?))bysO?(1). • The weak version with boundsO(1/?)is known to follow from the Fourier

Entropy-Influence Conjecture.

• Proved for “almost all" polynomial-size DNF formulas (appropriately defined) by Klivans, Lee, and Wan [

KLW10].

• Mansour [ Man95] obtained the upper-bound (s/?)O(loglog(s/?)log(1/?)).

Bernoulli Conjecture

Statement:LetTbe a finite collection of vectors in ?n. Defineb(T)= E x≂{-1,1}n[maxt?T?t,x?], and defineg(T) to be the same quantityexcept withx≂ ?nGaussian. Then there exists a finite collection of vectorsT?such that

Source:[

Tal94]

5

Remarks:

• The quantityg(T) is well-understood in terms of the geometry ofT, thanks to Talagrand"s majorizing measures theorem. • Talagrand offers a $5000 prize for proving this, and a $1000prize for disproving it.

Fourier Entropy-Influence Conjecture

Statement:There is a universal constantCsuch that for anyf:{-1,1}n→

S?f(S)2log21

?f(S)2is the spectral entropy andI[f] is the total influence.

Source:[

FK96]

Remarks:

• Proved for “almost all" polynomial-size DNF formulas (appropriately defined) by Klivans, Lee, and Wan [

KLW10].

• Proved for symmetric functions and functions computable by read-once decision trees by O"Donnell, Wright, and Zhou [

OWZ11].

• An explicit example showing thatC≥60/13 is necessary is known. (O"Donnell, unpublished.) • Weaker version: the “Min-Entropy-InfluenceConjecture",which states that there existsSsuch that?f(S)2≥2-C·I[f]. This conjecture is strictly stronger than the KKL Theorem, and is implied by the KKL Theorem in the case of monotone functions.

Majority Is Least Stable Conjecture

Statement:Letf:{-1,1}n→{-1,1}be a linear threshold function,nodd. Then for allρ?[0,1],Stabρ[f]≥Stabρ[Majn].

Source:[

BKS99]

Remarks:

2

π?δ+o(?δ).

• The best result towards the weaker version is Peres"s Theorem [

Per04],

2

π?δ+O(δ3/2).

• By takingρ→0, the conjecture has the following consequence, which is also open: Letf:{-1,1}n→{-1,1}be a linear threshold function withE[f]=0. Then?n i=1?f(i)2≥2

π. The best known lower bound here

is 1

2, which follows from the Khinchine-Kahane inequality; see [GL94].

6 Optimality of Majorities for Non-Interactive Correlation

Distillation

Statement:Fixr?

?,nodd, and 0Source:[

MO05] (originally from 2002)

Remarks:

• It is possible (e.g., forr=10,n=5,?=.26) for neither the Dictator (Maj

1) nor full Majority (Majn) to be maximizing.

Noise Sensitivity of Intersections of Halfspaces

Statement:Letf:{-1,1}n→{-1,1}be the intersection (AND) ofklinear logk)·?δ.

Source:[

KOS02]

Remarks:

• The boundO(k)·? δfollows easily from Peres"s Theorem and is the best known. • The “Gaussianspecial case" follows easily from the work ofNazarov[

Naz03].

• An upper bound of the form polylog(k)·δΩ(1)holds if the halfspaces are sufficiently “regular" [

HKM10].

Non-Interactive Correlation Distillation with Erasures Statement:Letf:{-1,1}n→{-1,1}be an unbiased function. Letz≂ {-1,0,1}nbe a “random restriction" in which each coordinateziis (indepen- dently)±1 with probabilityp/2 each, and 0 with probability 1-p. Assuming p<1/2 andnodd, is it true thatEz[|f(z)|] is maximized whenfis the ma- jority function? (Here we identifyfwith its multilinear expansion.)

Source:[

Yan04]

Remarks:

• Forp≥1/2, Yang conjectured thatEz[|f(z)|] is maximized whenfis a dictator function; this was proved by O"Donnell and Wright [

OW12].

• Mossel [ Mos10] shows that iff"s influences are assumed at mostτthen E

Triangle Removal in

?n

2Statement:LetA?

?n

2. Suppose that?2nelements must be removed

fromAin order to make it “triangle-free" (meaning there does not exist 7 x,y,x+y?A). Is it true thatPrx,y[x,y,x+y?A]≥poly(?), wherexandy are independent and uniform on ?n 2?

Source:[

Gre05a]

Remarks:

• Green [ Gre05a] showed the lower bound 1/(2↑↑?-Θ(1)). • Bhattacharyya and Xie [

BX10] constructed anAfor which the proba-

bility is at most roughly?3.409.

Subspaces in Sumsets

Statement:Fix a constantα>0. LetA?

?n

2have density at leastα. Is it

true thatA+Acontains a subspace of codimensionO(? n)?

Source:[

Gre05a]

Remarks:

• The analogousproblem for the groupZNdates back to Bourgain [

Bou90].

n)}, it is easy to show that codimensionO(? n) cannot be improved. This example is essentially due to Ruzsa [

Ruz93], see [Gre05a].

• The best bounds are due to Sanders [

San10a], who shows thatA+A

must contain a subspace of codimension?n/(1+log2(1-α

1-2α))?. Think-

ing ofαas small, this means a subspace ofdimensionroughlyα ln2· n. Thinking ofα=1/2-?for?small, this is codimension roughly n/log2(1/?). In the same work Sanders also shows that ifα≥1/2- .001/? nthenA+Acontains a subspace of codimension 1. • As noted in the remarks on the Polynomial Freiman-Ruzsa/Bogolyubov Conjectures, it is also interesting to consider the relaxedproblem where we only require thatA+Acontains 99% of the points in a large sub- space. Here it might be conjectured that the subspace can have codi- mensionO(log(1/α)).

Aaronson-Ambainis Conjecture

Statement:Letf:{-1,1}n→[-1,1] have degree at mostk. Then there existsi?[n] withInfi[f]≥(Var[f]/k)O(1).

Source:[

Aar08,AA11]

Remarks:

• True forf:{-1,1}n→{-1,1}; this follows from a result of O"Donnell,

Schramm, Saks, and Servedio [

OSSS05].

• The weaker lower bound (Var[f]/2k)O(1)follows from a result of Dinur,

Kindler, Friedgut, and O"Donnell [

DFKO07].

8

Bhattacharyya-Grigorescu-Shapira Conjecture

Statement:LetM?

?m×k

2andσ?{0,1}k. Say thatf:

?n

2→{0,1}is (M,σ)-

freeif there does not existX=(x(1),...,x(k)) (where eachx(j)? ?n

2is a row

vector) such thatMX=0 andf(x(j))=σjfor allj?[k]. Now fix a (possi- bly infinite) collection{(M1,σ1),(M2,σ2),···}and consider the propertyPn of functionsf: ?n

2→{0,1}thatfis (Mi,σi)-free for alli. Then there is a

one-sided error, constant-query property-testing algorithm forPn.

Source:[

BGS10]

Remarks:

• The conjecture is motivated by a work of Kaufman and Sudan [ KS08] which proposes as an open research problem the characterization of testability for linear-invariant properties of functionsf: ?n

2→{0,1}.

The properties defined in the conjecture are linear-invariant. • Every property family (Pn) defined by{(M1,σ1),(M2,σ2),···}-freeness issubspace-hereditary; i.e., closed under restriction to subspaces. The converse also “essentially" holds. [

BGS10].

• ForMof rank one, Green [

Gre05a] showed that (M,1k)-freeness is

testable. He conjectured this result extends to arbitraryM; this was confirmed by Král", Serra, and Vena [

KSV08] and also Shapira [Sha09].

Austin [

Sha09] subsequentlyconjectured that (M,σ)-freeness is testablequotesdbs_dbs1.pdfusesText_1
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